[LARTC] about default filter command

[Vincent Dautremont <vdautrem@ulb.ac.be>]

Hi,

here I have another newcomer question :-)

in the section 9.6.1 of this how too 

http://tldp.org/HOWTO/Adv-Routing-HOWTO/lartc.qdisc.filters.html

we can read commands about filters :

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# tc filter add dev eth0 protocol ip parent 10: prio 1 u32 match \ 

  ip dport 22 0xffff flowid 10:1

# tc filter add dev eth0 protocol ip parent 10: prio 1 u32 match \

  ip sport 80 0xffff flowid 10:1

# tc filter add dev eth0 protocol ip parent 10: prio 2 flowid 10:2

What does this say? It says: attach to eth0, node 10: a priority 1 u32 filter that matches on IP destination port 22 *exactly* and send it to band 10:1. And it then repeats the same for source port 80. The last command says that anything unmatched so far should go to band 10:2, the next-highest priority.

------------------------------------------

i try to do this at home as i want my ssh traffic prioritary to other traffic but the problem is with the last command ! it simply don't work. The last command that says default trafic goes to prio 2 doesn't work

# tc filter add dev eth0 protocol ip parent 10: prio 2 flowid 10:2

just give me the error: "Unknown filter flowid, hence option 1:2 is unparsable"

So I don't get what do I must do in order to say that the default trafic goes on priority 2 of the prio filter

is this how too always valid with the current version of tc ? did i do something wrong ?

Thank you for your help.

Vincent.

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